The distance between the directrices of the conic $\sqrt{(x - 5)^2 + (y - 4)^2} + \sqrt{(x - 3)^2 + (y - 2)^2} = 6$ is

  • A
    $9\sqrt{2}$
  • B
    $2\sqrt{2}$
  • C
    $4$
  • D
    $\frac{9}{\sqrt{2}}$

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